meghanaanandp
meghanaanandp meghanaanandp
  • 04-07-2019
  • Mathematics
contestada

Solve: The diagonals of a parallelogram are as follows:
AO=5y+1
OC=6y-1
DO=2(x+1)
OB=3x-1

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Аноним Аноним
  • 04-07-2019

Answer:

x = 3, y = 2.

Step-by-step explanation:

I assume that O is the point of intersection of the diagonals. The diagonals of a parallelogram bisect each other so here we have AO = OC and DO = OB.

Therefore 5y + 1 = 6y - 1

1 + 1 = 5y - 5y

2 = y.

2(x + 1) = 3x - 1

2x + 2 = 3x - 1

2 + 1 = 3x - 2x

3 = x.

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